求翻译：图5所示其编码时序仿真波形图，图中，clk2x采用2MHz的时钟，nrz为串行输入的归零制码(10101100)，meo为串行输出的曼彻斯特码。由图可见，从刚开始的跳变沿之后，输出meo也为10101100，证明编码过程正确。是什么意思？

Figure 5 shows the timing simulation waveforms of the encoding clk2x using a 2MHz clock nrz serial input of the return to zero code (10.1011 million), meo serial output of the Manchester code. The figure shows, from the beginning after the jump along the output meo also 10,101,100 to prove that the

the one shown in Figure 5 its coding sequence simulation waveform diagram, in which, with a 2 X 2 clk MHz nrz, the clock for the serial input of the zero system code (10.1011 million), meo is a serial output of Manchester. The figure shows, from the beginning, after jumping out meo along to 10.1011

Shown in Figure 5 its code succession simulation oscillogram, in the chart, clk2x uses 2MHz the clock, nrz is serial input nulling operation system code (10101100), meo is the serial output Manchester code.The figure shows, from the jump which just starts along after, outputs meo also was 10101100,

The coding sequence simulation waveform shown in Figure 5, figure, clk2x 2MHz clock, NRZ serial-input-zero code (10101100), MEO for the serial output of the Manchester code. Seen from the figure, after the hopping along from the very beginning, the output MEO 10.1011 million, proved correct the enco

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