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  • 匿名
关注:1 2013-05-23 12:21

求翻译:因此,同一时刻,如果各位位选线都处于选通状态的话,8位LED将显示相同的字符。若要各位LED能够显示出与本位相应的显示字符,就必须采用扫描显示方式,即在某一位的位选线处于选通状态时,其它各位的位选线处于关闭状态,是什么意思?

待解决 悬赏分:1 - 离问题结束还有
因此,同一时刻,如果各位位选线都处于选通状态的话,8位LED将显示相同的字符。若要各位LED能够显示出与本位相应的显示字符,就必须采用扫描显示方式,即在某一位的位选线处于选通状态时,其它各位的位选线处于关闭状态,
问题补充:

  • 匿名
2013-05-23 12:21:38
Therefore, the same time, if you line selection in a gating state, 8 led will show the same character. Members led To be able to display corresponding to the standard display character, you must use the scan shows a bit line selection in a selected state, you line selection is turned off.
  • 匿名
2013-05-23 12:23:18
Therefore, the same time, if you are in a selected line-state, 8-bit LED will display the same characters. If you want to be able to demonstrate that LED base corresponding to the displayed characters must be in the show, that in a bit of a pass-through option is selected, and the other members when
  • 匿名
2013-05-23 12:24:58
Therefore, identical time, if each position route selection all is at the selection condition, 8 LED will demonstrate the same character.If each LED can demonstrate with the standard corresponding demonstration character, must use the scanning display mode, namely is at the selection condition when
  • 匿名
2013-05-23 12:26:38
Therefore, the same time, if you selected lines are in gated, 8-digit LED shows the same characters. LED to show to you corresponding to the standard display of characters, you must use scanning display, that is, a route is selected through State, other members of the alignment is off,
  • 匿名
2013-05-23 12:28:18
正在翻译,请等待...
 
 
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