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  • 匿名
关注:1 2013-05-23 12:21

求翻译:For an N-bit by N-bit Wallace multiplier, the number of half adders is roughly proportional to N1:5 which results in the second phase of Wallace multipliers being more complex and larger than that of Dadda multipliers which use N  1 half adders.是什么意思?

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For an N-bit by N-bit Wallace multiplier, the number of half adders is roughly proportional to N1:5 which results in the second phase of Wallace multipliers being more complex and larger than that of Dadda multipliers which use N  1 half adders.
问题补充:

  • 匿名
2013-05-23 12:21:38
n位华莱士乘数为n位,半加器的数量大致成正比N1:5导致在第二阶段更复杂的和大于dadda乘法器使用N 1个半加器的华莱士乘数。
  • 匿名
2013-05-23 12:23:18
正在翻译,请等待...
  • 匿名
2013-05-23 12:24:58
为N位由N位华莱士乘算器,半加器的数量与N1是大致比例:5大于那导致的第二个阶段华莱士乘算器更加复杂和使用N  1半加器的Dadda乘算器。
  • 匿名
2013-05-23 12:26:38
N-N-一点一滴华莱士乘数,对于 N1:5,结果在第二阶段的华莱士乘数正在更复杂、 更比使用 N  1 半加法器的 Dadda 乘子的大成比例半加法器的数目。
  • 匿名
2013-05-23 12:28:18
For an N-bit by N-bit Wallace multiplier, the number of half adders is roughly proportional to N1:5 which results in the second phase of Wallace multipliers being more complex and larger than that of Dadda multipliers which use N  1 half adders.
 
 
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