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  • 匿名
关注:1 2013-05-23 12:21

求翻译:从上图的分析中可以得到曲面的最小半径为1.237,也就是说最大能薄壳(shell1)1.237的平均料厚。假如现在的模型要shell 1.5料厚的话就会造成失败。那我们要采取什么样的措施才能让模型最终生成1.5mm的料厚呢?解决方法有两种,但是都有个前提,得到的料厚不再是等料厚的了,这是因为本身曲面曲率的原因,模型已经不可能可以shell等料厚了,我们需要对这个部分作特殊处理是什么意思?

待解决 悬赏分:1 - 离问题结束还有
从上图的分析中可以得到曲面的最小半径为1.237,也就是说最大能薄壳(shell1)1.237的平均料厚。假如现在的模型要shell 1.5料厚的话就会造成失败。那我们要采取什么样的措施才能让模型最终生成1.5mm的料厚呢?解决方法有两种,但是都有个前提,得到的料厚不再是等料厚的了,这是因为本身曲面曲率的原因,模型已经不可能可以shell等料厚了,我们需要对这个部分作特殊处理
问题补充:

  • 匿名
2013-05-23 12:21:38
Can be obtained from the above analysis, the minimum radius of the surface to 1.237, meaning that the maximum shell (shell1) 1.237, the average material thickness. Now model the shell 1.5 feed thick it will cause a failure. That we have to take what measures to make the model the resulting material
  • 匿名
2013-05-23 12:23:18
From the above analysis can be curved in the minimum radius to 1.237 , that is the maximum that can thin Shell (Shell 1) The average 1.237 meter thick. Now if you want to shell the model 1.5 meter thick would be caused to fail. Then we have to take what measures to take to get the resulting model of
  • 匿名
2013-05-23 12:24:58
May obtain the curved surface minimum radius from in on chart analysis is 1.237, in other words, can the thin shell (shell1)1.237 average material be thick most greatly.If the present model wants the shell 1.5 material thick speeches to be able to create the defeat.What type then we do want to adopt
  • 匿名
2013-05-23 12:26:38
正在翻译,请等待...
  • 匿名
2013-05-23 12:28:18
 
 
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