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  • 匿名
关注:1 2013-05-23 12:21

求翻译:将还原性较强的金属作为保护极,与被保护金属相连构成原电池,还原性较强的金属将作为负极发生氧化反应而消耗,被保护的金属作为正极就可以避免腐蚀。是什么意思?

待解决 悬赏分:1 - 离问题结束还有
将还原性较强的金属作为保护极,与被保护金属相连构成原电池,还原性较强的金属将作为负极发生氧化反应而消耗,被保护的金属作为正极就可以避免腐蚀。
问题补充:

  • 匿名
2013-05-23 12:21:38
Restore the strong metal as a protective pole constitute the primary cell connected to the metal to be protected, reducing the strong metal oxidation reaction as a negative consumption, you can avoid corrosion protected metal as a cathode.
  • 匿名
2013-05-23 12:23:18
Will be back with a strong character of the metal as a protection, and the protection of metal connected to restore primary with a strong character of metal will be used as a negative response and carbon dioxide consumption, and the protection of the metal as a positive to avoid corrosion.
  • 匿名
2013-05-23 12:24:58
The reducible strong metal took the protection, with is protected extremely the metal to constitute connected the galvanic battery, the reducible strong metal occurs as the cathode the oxidizing reaction to consume, the metal which protects as the positive electrode may avoid corroding.
  • 匿名
2013-05-23 12:26:38
Of restoring stronger metals as protection, and is connected to the metal structure of the original battery, reducing strong metal as an anode oxidation reaction occurs and consumption, corrosion protected metal as cathode can be avoided.
  • 匿名
2013-05-23 12:28:18
正在翻译,请等待...
 
 
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