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  • 匿名
关注:1 2013-05-23 12:21

求翻译:decode c1⊕c2 immediately (current value of cu1=cu2=1). The algorithm then scan the next packet c2 and stores it as the first prospective coding packet, and the Tx then transmit c3. Since c2 and c3 satisfy CodingBenefit() and ColumnsBenefit()是什么意思?

待解决 悬赏分:1 - 离问题结束还有
decode c1⊕c2 immediately (current value of cu1=cu2=1). The algorithm then scan the next packet c2 and stores it as the first prospective coding packet, and the Tx then transmit c3. Since c2 and c3 satisfy CodingBenefit() and ColumnsBenefit()
问题补充:

  • 匿名
2013-05-23 12:21:38
  • 匿名
2013-05-23 12:23:18
2立即解码c1⊕c(当前值的cu1=cu2=1)。 然后,扫描算法的下一个数据包c2并将其存储在第一次编码数据包和tx然后传输c3。 因为c2和c3满足codingbenefit()和columnsbenefit()
  • 匿名
2013-05-23 12:24:58
  • 匿名
2013-05-23 12:26:38
  • 匿名
2013-05-23 12:28:18
 
 
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