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  • 匿名
关注:1 2013-05-23 12:21

求翻译:UNION 运算符通过组合其他两个结果表(例如 TABLE1 和 TABLE2)并消去表中任何重复行而派生出一个结果表。当 ALL 随 UNION 一起使用时(即 UNION ALL),不消除重复行。两种情况下,派生表的每一行不是来自 TABLE1 就是来自 TABLE2。是什么意思?

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UNION 运算符通过组合其他两个结果表(例如 TABLE1 和 TABLE2)并消去表中任何重复行而派生出一个结果表。当 ALL 随 UNION 一起使用时(即 UNION ALL),不消除重复行。两种情况下,派生表的每一行不是来自 TABLE1 就是来自 TABLE2。
问题补充:

  • 匿名
2013-05-23 12:21:38
The union operator through a combination of the results of the other two tables (for example, table1 and table2) and elimination in the table of any duplicate rows derived from a result table. All with the union when used in conjunction (ie, the union all), does not eliminate duplicate rows. In both
  • 匿名
2013-05-23 12:23:18
Portfolio UNION unary operator through two other results table (for example TABLE TABLE 1 and 2) and it has removed any duplication in the table are derived from a results table. When ALL UNION when used together with UNION ALL (i.e. , not eliminate duplication. Two circumstances, derived from table
  • 匿名
2013-05-23 12:24:58
The UNION operator through combines other two result table (e.g. TABLE1 and TABLE2) and eliminates in the table any repetition line to derive a result table.When ALL uses together along with UNION (i.e. UNION ALL), does not eliminate the redundant line.In two kind of situations, derivation table eac
  • 匿名
2013-05-23 12:26:38
UNION operator through a combination of the other two tables of results (for example, TABLE1 and TABLE2) and any duplicate rows in the deleted table and derive a result table. When ALL when it is used with the UNION (UNION ALL), does not eliminate duplicate rows. In two cases, derived not from TABLE
  • 匿名
2013-05-23 12:28:18
select count (*) as shuliang = '1 'from the table where stock = 10
 
 
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