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关注：1
2013-05-23 12:21
求翻译：示波探头衰减X1时，探头本身带宽小于6MHz，只有经过校正且探头衰减X10时，才能满足50MHz带宽（响应正弦波信号）。是什么意思？ 待解决
 悬赏分：1
- 离问题结束还有
示波探头衰减X1时，探头本身带宽小于6MHz，只有经过校正且探头衰减X10时，才能满足50MHz带宽（响应正弦波信号）。
问题补充： |
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2013-05-23 12:21:38
Oscilloscope X1 probe attenuation, the bandwidth of the probe itself is less than 6MHz, only after the probe attenuation correction and X10, the order to meet the 50MHz bandwidth (response to sine wave signal).
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2013-05-23 12:23:18
1 shows the probe attenuation X probe itself, when less than 6 MHz bandwidth, only after calibration and probe attenuation at 10, would be required to meet 50 X MHz bandwidth (Responding to sine wave signal).
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2013-05-23 12:24:58
Shows when the wave probe head weakens X1, the probe head itself band width is smaller than 6MHz, when weakens X10 after the adjustment also the probe head, can satisfy the 50MHz band width (response sine wave signal).
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2013-05-23 12:26:38
Oscillographic probe attenuation of X1, the bandwidth is less than 6MHz the probe itself, only after the probe attenuation of X10 while the correction in order to meet the 50MHz (response to sine wave signal).
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2013-05-23 12:28:18
Oscillographic probe attenuation of X1, the bandwidth is less than 6MHz the probe itself, only after the probe attenuation of X10 while the correction in order to meet the 50MHz (response to sine wave signal).
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