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关注：1
2013-05-23 12:21
求翻译：In numerical simulations of 4000TEU container vessel, the regular head waves were adopted as the incident wave , the wave-length λ were in the range from 0.3 to 4 times Lpp , and 16 wave-lengths were computed respectively with the wave amplitude of 2.83m. The Froude number based on Lpp equals 0.234.是什么意思？ 待解决
 悬赏分：1
- 离问题结束还有
In numerical simulations of 4000TEU container vessel, the regular head waves were adopted as the incident wave , the wave-length λ were in the range from 0.3 to 4 times Lpp , and 16 wave-lengths were computed respectively with the wave amplitude of 2.83m. The Froude number based on Lpp equals 0.234.
问题补充： |
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2013-05-23 12:21:38
4000TEU集装箱船的数值模拟，通过入射波，经常头波的波长λ的范围从0.3到4倍LPP，16波长度与2.83米波振幅分别计算。弗劳德数的基础上LPP等于0.234。
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2013-05-23 12:23:18
在数字模拟4000TEU的集装箱船舶,经常头浪的事件通过了波、波的波长λ是在范围从0.3至4倍LPP,和16浪长度分别计算的浪潮的振幅需要2.83m。 弗劳德的人数等于0.234根据LPP。
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2013-05-23 12:24:58
在4000TEU容器船的数值仿真，规则顶头波浪被采取了作为入射波，波长λ在范围从0.3到4次Lpp，并且16个波长计算了分别以波浪高度2.83m。 根据Lpp均等的Froude数字0.234。
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2013-05-23 12:26:38
波入射波，波长 λ 作为通过定期头在数值模拟 4000TEU 集装箱船，从 0.3 到 4 倍 Lpp 和 16 波长度被分别计算波振幅 2.83 米的范围内。基于 Lpp 佛氏数等于 0.234。
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2013-05-23 12:28:18
4000TEU集装箱船的数值模拟，通过入射波，经常头波的波长λ的范围从0.3到4倍LPP，16波长度与2.83米波振幅分别计算。弗劳德数的基础上LPP等于0.234。
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