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关注：1
2013-05-23 12:21
求翻译：A fast PID loop tuning usually overshoots slightly to reach the setpoint more quickly; however, some systems cannot accept overshoot, in which case an over-damped closed-loop system is required, which will require a setting significantly less than half that of the setting that was causing oscillation.是什么意思？ 待解决
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- 离问题结束还有
A fast PID loop tuning usually overshoots slightly to reach the setpoint more quickly; however, some systems cannot accept overshoot, in which case an over-damped closed-loop system is required, which will require a setting significantly less than half that of the setting that was causing oscillation.
问题补充： |
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2013-05-23 12:21:38
正在翻译，请等待...
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2013-05-23 12:23:18
调整一个快速的PID的圈有一点通常超越迅速到达调整点;然而，有些系统不可能接受调整量，在需要情况下一个过被阻止的闭环系统，比一半将要求一重大设置较少那设置导致动摆。
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2013-05-23 12:24:58
一个快速的PID圈调整轻微地通常超越迅速到达setpoint; 然而，有些系统不可能接受超越，在需要情况下一个在被阻止的闭环系统，显着比一半将要求一个设置那设置导致动摆。
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2013-05-23 12:26:38
通常将快速循环的 pid 飞过略更快 ； 到达设定点但是，有些系统不能接受过冲，在其中案件过度阻尼的闭环系统是必需的这就需要大大少于一半的设置的导致振荡的设置。
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2013-05-23 12:28:18
一个快速PID回路调节通常略有过度,达到设定点更快;但是,一些系统不能接受过冲,在这种情况下一个阻尼闭环系统是必需的,这将需要一个设置将大大少于一半的设置,会造成振荡。
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