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关注：1
2013-05-23 12:21
求翻译：(4) Since operator ‘*’ on the top of the operator stack has higher priority than its previous one ‘+’ and higher than the current one ‘’, current value 3’ is used to execute multiplication with ‘2’ popped up from the value stack. The result is pushed back into the value stack, while current operator ‘’ is pushed into是什么意思？ 待解决
 悬赏分：1
- 离问题结束还有
(4) Since operator ‘*’ on the top of the operator stack has higher priority than its previous one ‘+’ and higher than the current one ‘’, current value 3’ is used to execute multiplication with ‘2’ popped up from the value stack. The result is pushed back into the value stack, while current operator ‘’ is pushed into
问题补充： |
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2013-05-23 12:21:38
（4）由于在操作堆栈的顶部运营商鈥鈥具有更高的优先级比它的前一个鈥鈥和比当前更高鈥鈥电流值3鈥用于与执行乘法鈥从值栈中弹出。其结果是推回值栈，而当前的操作者鈥鈥推入操作栈。
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2013-05-23 12:23:18
正在翻译，请等待...
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2013-05-23 12:24:58
正在翻译，请等待...
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2013-05-23 12:26:38
(4) 自运算符 '*' 上该运算符堆栈有更高的优先级比其前一个 '+' 和高于当前' '，3' 的当前值用于执行乘法与 2' 从堆栈中弹出值。结果值堆栈中，而当前运营商推回到 '' 推入运算符堆栈。
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2013-05-23 12:28:18
[4]由于操作员'*'的顶部上的堆栈操作的优先级高于其上一个一个'+',高于目前一个'',当前值3”用于执行乘法与'2'弹出堆栈的值。 结果是被推回到值栈,而当前操作员''将被推入操作堆栈中。
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